Main Formula
The Cosine Rule
It’s Easier Than It Seems GCSE Trigonometry
a2 =b2 +c2 −2bccos(A)
The Cosine Rule allows us to solve triangles that do not contain a right angle.
When students first see the Cosine Rule, many think the formula looks difficult. But the process is actually very repetitive and structured.
Every question follows the same idea:
identify the sides → substitute carefully → solve step-by-step
The biggest challenge is usually matching the correct angle with the correct opposite side.
C
A
a
b
AcB
Side a is opposite angle A
1
1. When should we use the Cosine Rule?
The Cosine Rule is used in non-right-angled triangles. It is especially useful in two situations:
1. when we know two sides and the angle between them; 2. when we know all three sides and need an angle.
Quick memory rule
If SOHCAHTOA does not work because there is no right angle, the Cosine Rule is often the next method to try.
Right-angled triangle Use SOHCAHTOA
Non-right triangle Use Cosine Rule
2
2. Understanding the Formula
The Cosine Rule is:
a2 =b2 +c2 −2bccos(A) At first glance, this formula looks complicated.
But the structure is actually simple.
side squared = side squared + side squared − adjustment The cosine part changes the answer depending on the size of the angle.
• Small angles create shorter opposite sides. • Large angles create longer opposite sides.
Smaller angle
Larger angle
3
3. Example — Finding a Missing Side
Question
Find the missing side x.
Step 1 — Identify what we know
We know:
5 cm, The angle is between the two known sides.
That means this is a Cosine Rule question.
8 cm
8 cm,
60◦
5 cm
60◦
x
We are trying to find the side opposite the angle. So:
a=x
Step 2 — Write the formula
a2 =b2 +c2 −2bccos(A) Step 3 — Substitute values carefully
Replace each letter with the correct number.
x2 = 52 + 82 − 2(5)(8) cos(60◦) Step 4 — Calculate powers first
Now evaluate the cosine.
So:
x2 =25+64−80cos(60◦) cos(60◦) = 0.5
x2 =25+64−80(0.5)
4
Step 5 — Simplify
Step 6 — Square root both sides
We need x, not x2.
So we square root both sides.
x2 =89−40 x2 = 49
√
x= 49 x=7
x = 7 cm
Always remember:
If the formula gives x2, the final step is square rooting.
5
4. Example — Finding a Missing Angle
Question
Find angle A.
Step 1 — Identify the opposite side
The angle we need is A.
The side opposite angle A is:
So:
The remaining sides are:
Step 2 — Rearranged formula
When finding an angle, it is easier to use:
Step 3 — Substitute values
Step 4 — Evaluate powers
9 cm
11 cm
a = 11
b=6, c=9
6 cm
11 cm
cos(A) = b2 +c2 −a2 2bc
62 +92 −112 2(6)(9)
cos(A) =
cos(A) =
cos(A) = −4
36+81−121 108
108
cos(A) ≈ −0.037
6
Step 5 — Use inverse cosine
At the moment we have the cosine value. But we need the angle itself.
So we use inverse cosine.
A = cos−1(−0.037) A ≈ 92◦
A ≈ 92◦
When finding an angle:
cos−1 is one of the most important calculator buttons.
7
5. Exercises
Exercise 1
Find the missing side x.
45◦
Solution
We know two sides and the angle between them. That means we use the Cosine Rule.
The side we are finding is opposite the angle. So:
10 cm
Write the formula:
Substitute:
Calculate powers:
Now evaluate the cosine:
Substitute:
a2 =b2 +c2 −2bccos(A)
x2 = 72 + 102 − 2(7)(10) cos(45◦) x2 =49+100−140cos(45◦) cos(45◦) ≈ 0.7071
x2 = 149 − 140(0.7071) x2 = 149 − 98.99
x2 ≈ 50.01
7 cm
x
a=x, b=7, c=10
8
Square root both sides:
√
x ≈
x ≈ 7.1
x ≈ 7.1 cm
50.01
9
Exercise 2
Find the missing side x.
Solution
We know:
6 cm
x
9 cm
9 cm, 110◦
The angle is between the known sides. So we use the Cosine Rule.
Calculate powers:
Now evaluate the cosine.
x2 = 62 + 92 − 2(6)(9) cos(110◦)
x2 =36+81−108cos(110◦)
110◦
cos(110◦) ≈ −0.342 Notice that the cosine is negative because the angle is obtuse.
Substitute:
x2 = 117 − 108(−0.342) Subtracting a negative becomes addition.
Now square root both sides:
x2 = 117 + 36.94 x2 ≈ 153.94
√
x ≈
x ≈ 12.4
x ≈ 12.4 cm 10
6 cm,
153.94
Exercise 3
Find angle A.
Solution
8 cm
7 cm
All three sides are known.
That means we use the Cosine Rule to find an angle.
The side opposite angle A is:
So:
Use the rearranged formula:
Substitute values:
Evaluate powers:
Now use inverse cosine:
7 cm
10 cm
a=7, b=8, c=10
cos(A) = b2 +c2 −a2 2bc
82 +102 −72 2(8)(10)
115 160
cos(A) = 0.71875
A = cos−1(0.71875) A ≈ 44◦
A ≈ 44◦ 11
cos(A) =
cos(A) = cos(A) =
64+100−49 160
Exercise 4
A triangular garden has sides of length 12 m and 15 m. The angle between them is 70◦.
Find the third side.
Solution
12 m
70◦
x
This is a real-life problem, but mathematically it is still a Cosine Rule question. We know two sides and the included angle.
Write the formula:
Calculate powers:
Evaluate the cosine:
Substitute:
Square root:
x2 = 122 + 152 − 2(12)(15) cos(70◦) x2 = 144 + 225 − 360 cos(70◦) cos(70◦) ≈ 0.342
x2 = 369 − 360(0.342) x2 = 369 − 123.12 x2 ≈ 245.88
√
x ≈
x ≈ 15.7
x ≈ 15.7 m
15 m
245.88
12
Exercise 5
A triangle has side lengths:
9cm, 11cm, 14cm Find the angle opposite the side of length 14 cm.
Solution
The angle we need is opposite the side of length 14 cm. So:
Use the rearranged formula:
Substitute:
Evaluate powers:
Now use inverse cosine:
a=14, b=9, c=11
cos(A) = b2 +c2 −a2 2bc
92 +112 −142 2(9)(11)
6 198
cos(A) ≈ 0.0303
A = cos−1(0.0303) A ≈ 88◦
9 cm
14 cm
11 cm
cos(A) =
cos(A) = cos(A) =
81+121−196 198
A ≈ 88◦
Because the cosine value is very close to zero, the angle is very close to 90◦.
13
Exercise 6 — Real Life Application
A rescue team is planning a zipline across a canyon.
One side of the canyon is connected to a point that is 120 m away from the launch platform. Another support point is 85 m away from the same platform.
The angle between the two support cables is 48◦.
Find the distance between the two support points.
Give your answer to 1 decimal place.
Support Point 2
85 m x
48◦
120 m
This is a real-life problem involving distances and an angle. We know:
120 m, 85 m, The angle is between the two known sides.
That means this is a Cosine Rule question.
We are trying to find the side opposite the angle. So:
Solution
Write the Cosine Rule:
Substitute the values:
Calculate the powers first:
Now evaluate the cosine:
a=x, b=120, c=85
a2 =b2 +c2 −2bccos(A)
x2 = 1202 + 852 − 2(120)(85) cos(48◦)
x2 = 14400 + 7225 − 20400 cos(48◦) cos(48◦) ≈ 0.6691
Substitute this value:
Platform
Support Point 1
14
48◦
Multiply carefully:
x2 = 21625 − 20400(0.6691) x2 = 21625 − 13649.64
x2 ≈ 7975.36
√
x ≈
x ≈ 89.3
x ≈ 89.3 m
Now square root both sides to find x:
7975.36
Notice how this real-life problem still follows exactly the same steps:
identify the sides → substitute carefully → calculate step-by-step The context changes, but the mathematics stays the same.
15
6. Final Summary
1. Identify the opposite side carefully.
2. Match the angle with the correct side letter. 3. Substitute slowly and carefully.
4. Use brackets properly.
5. Use cos−1 for missing angles.
6. Square root at the end for missing sides.
match the sides → substitute carefully → solve step-by-step
Final Checklist
• Is the calculator in degree mode?
• Did you identify the opposite side correctly? • Did you use inverse cosine for angles?
• Did you square root at the end for sides?
16
Leave a Reply